# Line slope calculator 4x-9y=-18

**Straight line given by points A[0; 2] and B[9; 6]**

## Calculation:

**Slope-intercept form of line:**y = 0.4444x+2

**Canonical form of the line equation:**4x-9y+18 = 0

**Parametric form of the line equation:**

x = 9t

y = 4t+2 ; t ∈ R

**Slope:**m = 0.4444

**Slope angle of line: φ =**23°57'45″ = 0.4182 rad

**X intercept:**x

_{0}= -4.5

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.8276

**The length of the segment AB: |AB| =**9.8489

**Vector: AB =**(9; 4)

**Normal vector: n =**(4; -9)

**Midpoint of the segment AB: M =**[4.5; 4]

**Perpendicular Bisector equation:**9x+4y-56.5 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (9; 6) ; |OB| = 10.8167**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 56°18'36″ = 0.9828 rad**